Question
A’s age is 150% of what he was 6 years ago, But 50% of
what it will be after 6 years. What is his present age?Solution
Let present age of A be x years. => 150% of (x - 6) = 50% of (x + 6) => 3(x - 6) = (x + 6) => 3x – 18 = x + 6 => x = 12 years
tan 1˚ × tan 2˚× …………………….tan 88˚ × tan 89˚ = ?
Calculate the maximum and minimum value of (8cosA + 15sinA + 15), if 'q' lies in the first quadrant.
Solve for x in the interval [0, 2π]: 2 sin²x + 3 sinx - 2 = 0.

Find the value of the given trigonometric expression:
(sin 10°cos 80° + cos²10°) × sin 30° + (cos 60°tan 45°) × sec 60°
...- Find the maximum value of (11sin A + 60cos A).
The minimum value of 45 sin2 θ + 28 cos2 θ is
sin2 17˚ + sin2 19˚ + sin2 21˚ + sin2 23˚ + ……… + sin2 77˚ = ?
- Simplify the following trigonometric expression:
9 sin 36° csc 54° − 7 tan 47° cot 43°