Question
The present ages of a father and his son are in the
ratio 7 : 3. If 8 years ago the father was three times as old as his son, what is the present age of the father?Solution
ATQ, Let present ages be: Father = 7k years Son = 3k years 8 years ago: Father = 7k − 8 Son = 3k − 8 Given: 8 years ago, father was 3 times as old as son: 7k − 8 = 3(3k − 8) 7k − 8 = 9k − 24 −8 + 24 = 9k − 7k 16 = 2k k = 8 Father’s present age = 7k = 7 × 8 = 56 years
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