Question

    Present average age of 4 friends: ‘A’, ‘B’,

    ‘C’ and ‘D’ is 36 years. If their ages are in the arithmetic progression in the same order and ‘D’ is 4 years older than ‘B’, then find the sum of present ages of ‘A’ and ‘C’.
    A 75 years Correct Answer Incorrect Answer
    B 72 years Correct Answer Incorrect Answer
    C 70 years Correct Answer Incorrect Answer
    D 71 years Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Common difference between ages = (4/2) = 2 years. So, let present ages of ‘A’, ‘B’, ‘C’ and ‘D’ be ‘x’, (x + 2) years, (x + 4) years and (x + 6) years, respectively According to question: x + x + 2 + x + 4 + x + 6 = 144 Or, 4x = 132 Or, x = 33 years (Age of A) Present age of ‘C’ = x + 4 = 33 + 4 = 37 years Required sum = 33 + 37 = 70 years

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