Question
Present average age of 4 friends: ‘A’, ‘B’,
‘C’ and ‘D’ is 36 years. If their ages are in the arithmetic progression in the same order and ‘D’ is 4 years older than ‘B’, then find the sum of present ages of ‘A’ and ‘C’.Solution
Common difference between ages = (4/2) = 2 years. So, let present ages of ‘A’, ‘B’, ‘C’ and ‘D’ be ‘x’, (x + 2) years, (x + 4) years and (x + 6) years, respectively According to question: x + x + 2 + x + 4 + x + 6 = 144 Or, 4x = 132 Or, x = 33 years (Age of A) Present age of ‘C’ = x + 4 = 33 + 4 = 37 years Required sum = 33 + 37 = 70 years
Who is Grandson of O?
Answer the questions based on the information given below.
Nine persons G, K, M, F, H, J, I, N and L are there in the family of three generat...
P is the brother of Q. S is the father of P. R is the brother of S. If T is the mother of R, then how is P related to T?
How is the mother of J related to the daughter of H?
How is P related to M’s son?
How is S related to Z?
How many daughters Ajay and Rekha have?
...Answer the questions based on the information given below.
Seven persons (S, T, U, V, W, Y and Z) belong to a family of three generations. No s...
How is G related to H?
If V is married to M then how is V related to the daughter of H?