Question
Present average age of 4 friends: ‘A’, ‘B’,
‘C’ and ‘D’ is 36 years. If their ages are in the arithmetic progression in the same order and ‘D’ is 4 years older than ‘B’, then find the sum of present ages of ‘A’ and ‘C’.Solution
Common difference between ages = (4/2) = 2 years. So, let present ages of ‘A’, ‘B’, ‘C’ and ‘D’ be ‘x’, (x + 2) years, (x + 4) years and (x + 6) years, respectively According to question: x + x + 2 + x + 4 + x + 6 = 144 Or, 4x = 132 Or, x = 33 years (Age of A) Present age of ‘C’ = x + 4 = 33 + 4 = 37 years Required sum = 33 + 37 = 70 years
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Only few Letters are Numbers
All Digits are Alphabets
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Some children are parents.
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Only Subjective are Information.
A few Subjective are Solutions.
Conclusion...
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All ribbons are mat.
Some mats are ropes.
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No blue is black.
Only a few blacks are Whites.
All Whites are grey.
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All Sticks are Containers.
Conclusions:
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