Question
Present average age of 4 friends: ‘A’, ‘B’,
‘C’ and ‘D’ is 36 years. If their ages are in the arithmetic progression in the same order and ‘D’ is 4 years older than ‘B’, then find the sum of present ages of ‘A’ and ‘C’.Solution
Common difference between ages = (4/2) = 2 years. So, let present ages of ‘A’, ‘B’, ‘C’ and ‘D’ be ‘x’, (x + 2) years, (x + 4) years and (x + 6) years, respectively According to question: x + x + 2 + x + 4 + x + 6 = 144 Or, 4x = 132 Or, x = 33 years (Age of A) Present age of ‘C’ = x + 4 = 33 + 4 = 37 years Required sum = 33 + 37 = 70 years
324 322 640 1914 7648 ? 229368
...12Â Â Â Â Â 13Â Â Â Â Â Â 22Â Â Â Â Â Â 47Â Â Â Â Â 96Â Â Â Â Â ?
...5     9      36      ?       177      213
...Complete the series: 5, 20, 24, 6, 2, 8,?
Identify the logic of the below given series and given answer.
Series I :: 81, 89, 116, 241, (A), 1915
Series II :: (B), 204, 208, 4...
The following expressions form a series followed by a (?). Find the odd one out first and then find that what will come in place of the question mark (?...
120     119     ?     352      2464     2455
...24, 12, 18, ?, 157.5, 708.75
640 320 160 ? 40 20
6000 3002 1503 ? 378.75 191.375 97.6875
...
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