Question
There are three friends, A, B, and C, whose ages are in the
ratio 4 : 7 : 6. If the average age of A, B, and C is 102 years, then find the difference (in years) between the age of the oldest and the youngest.Solution
The ratio of the ages of A, B, and C = 4 : 7 : 6
The total sum of their ages = 102 X 3 = 306 years
17x = 306
x = 306 / 17
x = 18
Difference = 7x - 4x = 3 X 18 = 54 years
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