There are five numbers A, B, C, D and E. The ratio

Solution

The number C is 12.5% more than the number E. Let’s assume the number E is ‘8z’. Number C = (100+12.5)% of 8z = 112.5% of 8z = 9z The number C is 50% more than the number D. 9z = (100+50)% of the number D 9z = 150% of the number D number D = 9z/1.5 = 6z The average of the number B and C is 38. (number B + number C)/2 = 38 (number B + number C) = 76 (number B + 9z) = 76 number B = (76-9z) The number A is five less than the number B. number A = (number B - 5) = (76-9z)-5 = (71-9z) If the number D is 8 less than the number E. 6z = 8z-8 8z-6z = 8 2z = 8 z = 4 The ratio between the numbers of B and D is (y+1) : 3 respectively. (76-9z)/6z = (y+1)/3 Put the value of ‘z’ in the above equation. (76-9x4)/(6x4) = (y+1)/3 (76-36)/(2x4) = (y+1)/1 40/8 = (y+1)/1 (y+1) = 5 Value of ‘y’ = 5-1 = 4