Question
The ratio of age of βMβ 8 years ago to the age of
βNβ 2 years hence from now is 1 : 2. If the sum of their present ages is 50 years, then find the age of βNβ 4 years hence from now.Solution
Let the present ages of βMβ and βNβ be βpβ years and βqβ years respectively. Then,
p + q = 50 Or,
q = 50 β p ATQ, [{(p - 8)}/{(q + 2)} = {1/2}] Or, 2(p β 8) = q + 2 Or, 2p β 16 = q + 2 Or, 2p β q = 18 Or, 2p β (50 β p) = 18 Or, 3p = 68 Or, p = 24 Or, q = 50 β 24 = 26 Therefore, age of βNβ 4 years hence from now = 26 + 4 = 30 years
61, 48, ?, 35, 87, 22
92,Β Β 51,Β Β 21,Β Β 13.5,Β Β x,Β Β 4.25
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