Question
Present age of ‘A’ is 40% more than that of ‘B’.
If 11 years hence from now, ‘B’ will be 5 years younger than ‘A’, then find the sum of present ages of ‘A’ and ‘B’.Solution
Let present age of ‘B’ be ‘x’ years Present age of ‘A’ = x × 1.40 = ‘1.40x’ years ATQ; (x + 11) + 5 = (1.40x + 11) Or, x + 16 = 1.40x + 11 Or, 5 = 0.40x Or, x = 12.5 So, present age of ‘B’ = 12.5 years And, present age of ‘A’ = 12.5 + 5 = 17.5 years Required sum = 12.5 + 17.5 = 30 years
I. 6y2 – 23y + 20 = 0
II. 4x2 – 24 x + 35 = 0
The quadratic equation (p + 1)x 2 - 8(p + 1)x + 8(p + 16) = 0 (where p ≠ -1) has equal roots. find the value of p.
I. 56x² - 99x + 40 = 0
II. 8y² - 30y + 25 = 0
I. 2x² - 7x + 3 = 0
II. 8y² - 14y + 5 = 0
I. x2 - 9x - 52 = 0
II. y2 - 16y + 63 = 0
I. y² + y – 56 = 0
II. 2x² + 11 x – 40 = 0
I. 2p2 + 25p – 13 = 0
II. 2q2 – 19q = 2q + 23
I. 2x² - 9x + 10 = 0
II. 3y² + 11y + 6 = 0
I. x2 + 24x + 143 = 0
II. y2 + 12y + 35 = 0
I. x2 – 13x + 36 = 0
II. 3y2 – 29y + 18 = 0
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