Question
Present age of ‘A’ is 40% more than that of ‘B’.
If 11 years hence from now, ‘B’ will be 5 years younger than ‘A’, then find the sum of present ages of ‘A’ and ‘B’.Solution
Let present age of ‘B’ be ‘x’ years Present age of ‘A’ = x × 1.40 = ‘1.40x’ years ATQ; (x + 11) + 5 = (1.40x + 11) Or, x + 16 = 1.40x + 11 Or, 5 = 0.40x Or, x = 12.5 So, present age of ‘B’ = 12.5 years And, present age of ‘A’ = 12.5 + 5 = 17.5 years Required sum = 12.5 + 17.5 = 30 years
10, 22, 46, ?, 130, 190
10                          15                          ?                    �...
2, A, 9, B, 6, C, 13, D, ?
Direction: Which of the following will replace ‘?’ in the given question?
342, ‘?’, 420, 462, 506, 552, 60
2342 2223 2090 1943 1782 ?
...7, 26, 238, 962, 8522, 34078
Complete the series choosing the missing number.
8, 13, 20, ____, 40.
In the question, three series I, II and III are given. Find the value of x, y and z to establish the correct relation among them and choose the correct...
800    544    416    352    ?     304
19, 37, 65, 91, 127, 169