Question
Present age of βAβ is 40% more than that of βBβ.
If 11 years hence from now, βBβ will be 5 years younger than βAβ, then find the sum of present ages of βAβ and βBβ.Solution
Let present age of βBβ be βxβ years Present age of βAβ = x Γ 1.40 = β1.40xβ years ATQ; (x + 11) + 5 = (1.40x + 11) Or, x + 16 = 1.40x + 11 Or, 5 = 0.40x Or, x = 12.5 So, present age of βBβ = 12.5 years And, present age of βAβ = 12.5 + 5 = 17.5 years Required sum = 12.5 + 17.5 = 30 years
From the given answer figures, select the one in which the question figure is hidden / embedded(rotation is not allowed).
Select the answer figure in which the question figure is hidden ?
Find out the alternative figure which contains figure (X) as its part.
Select the option that is embedded in the given figure.
Select the option figure which is embedded in the given figure. (Rotation is not allowed).
From the given answer figures, select the one in which the question figures is hidden.

In each of the following questions, you are given a figure (X) followed by four alternative figures (1), (2), (3) and (4) such that figure (X) is embed...
Select the option figure which is embedded in the given figure. (Rotation is not allowed).
