Question
Present age of ‘A’ is 40% more than that of ‘B’.
If 11 years hence from now, ‘B’ will be 5 years younger than ‘A’, then find the sum of present ages of ‘A’ and ‘B’.Solution
Let present age of ‘B’ be ‘x’ years Present age of ‘A’ = x × 1.40 = ‘1.40x’ years ATQ; (x + 11) + 5 = (1.40x + 11) Or, x + 16 = 1.40x + 11 Or, 5 = 0.40x Or, x = 12.5 So, present age of ‘B’ = 12.5 years And, present age of ‘A’ = 12.5 + 5 = 17.5 years Required sum = 12.5 + 17.5 = 30 years
1290, 1225, 1175, ?, 1112, 1095, 1085
48   49    45     54    ?      63      27
...√(10198 )× √(7220 )÷ 16.69 + 2010.375= ?
4, 4, 12, 60, ?, 3780
4    9    28    99    ?   2105   12660
...12, 27, ?, 113, 141, 285, 313
What will come in place of (?) Question mark in the given number series.
1, 2, 5, 14, 41, 122, ?
16.12 × 15.94 + 654.92 – 344.83 = ?× 5.95
306, 272, 240, ?, 182, 156
728, 737, ?, 778, 814, 863Â