Question
Present age of βAβ is 40% more than that of βBβ.
If 14 years hence from now, βBβ will be 8 years younger than βAβ, then find the sum of present ages of βAβ and βBβ.Solution
Let present age of βBβ be βxβ years Present age of βAβ = x Γ 1.40 = β1.40xβ years ATQ; (x + 14) + 8 = (1.40x + 14) Or, x + 22 = 1.40x + 14 Or, 8 = 0.40x Or, x = 20 So, present age of βBβ = 20 years And, present age of βAβ = 20 + 8 = 28 years Required sum = 20 + 28 = 48 years
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