Question
The sum of the ages of A and B is (3x + 10) years. 5
years ago, the ratio of their ages was 4:5. Find the present age of A, if B is 4 years older than A.Solution
Solution: Let A's age be y years and B's age be y + 4 years. According to the given condition, y + (y + 4) = 3x + 10 2y + 4 = 3x + 10 2y = 3x + 6 y = (3x + 6) / 2 5 years ago, the ratio of their ages was 4:5. So, (y - 5) / (y + 4 - 5) = 4/5 (y - 5) / (y - 1) = 4/5 Cross-multiply and solve for y: 5(y - 5) = 4(y - 1) 5y - 25 = 4y - 4 y = 21 Present age of A = 21 years
564.932 + 849.029 – 425.08 = 612.095 + ?
999.99 + 99.99 + 99= ?
A sum of ₹60,000 is invested at a compound interest rate of 'x%' per annum, compounded annually, and grows to ₹75,264 in 2 ye...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
³√? × 33.97 + 59.99 × 28.9 – 48.98 × 21.42 = 1085.344
1279.98 ÷ 40.48 × 10.12 = ? × 2.16
(124.901) × (11.93) + 219.95 = ? + 114.891 × 13.90
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
