Question
The sum of the ages of A and B is (3x + 10) years. 5
years ago, the ratio of their ages was 4:5. Find the present age of A, if B is 4 years older than A.Solution
Solution: Let A's age be y years and B's age be y + 4 years. According to the given condition, y + (y + 4) = 3x + 10 2y + 4 = 3x + 10 2y = 3x + 6 y = (3x + 6) / 2 5 years ago, the ratio of their ages was 4:5. So, (y - 5) / (y + 4 - 5) = 4/5 (y - 5) / (y - 1) = 4/5 Cross-multiply and solve for y: 5(y - 5) = 4(y - 1) 5y - 25 = 4y - 4 y = 21 Present age of A = 21 years
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