Question
Present average age of 4 friends: βAβ, βBβ,
βCβ and βDβ is 30 years. If their ages are in the arithmetic progression in the same order and βDβ is 4 years older than βBβ, then find the sum of present ages of βAβ and βCβ.Solution
Common difference between ages = (4/2) = 2 years. So, let present ages of βAβ, βBβ, βCβ and βDβ be βxβ, (x + 2) years, (x + 4) years and (x + 6) years, respectively According to question: x + x + 2 + x + 4 + x + 6 = 120 Or, 4x = 108 Or, x = 27 years (Age of A) Present age of βCβ = x + 4 = 27 + 4 = 31 years Required sum = 27 + 31 = 58 years
What is the primary function of the United Nations (UN)?
ΰ€Έΰ₯ΰ€΅ΰ₯ΰ€ ΰ€¨ΰ€Ήΰ€° ΰ€ΰ€Ώΰ€Έ-ΰ€ΰ€Ώΰ€Έΰ€ΰ₯ ΰ€ΰ₯ΰ€‘ΰ€Όΰ€€ΰ₯ ΰ€Ήΰ₯ ?
Β The headquarters of World Bank is situated in?
Who assassinated Michael O'Dwyer to avenge the Jallianwala Bagh Massacre?
What was the primary goal of the "Smart Cities Mission" launched by the Government of India?
The Union Ministry of Home Affairs (MHA) adjudged ________ police station as the best police station across the country in 2021.
Where was the first meeting for Individual Satyagraha held in 1940 in Garhwal?
The Full form of NCCC is
What is the Paik Strait?
Which of the following statements is/are true?
1. Generally, an unbalanced gender ratio is found in India's northern cities.
2.In contrast...
