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Common difference between ages = (4/2) = 2 years. So, let present ages of ‘A’, ‘B’, ‘C’ and ‘D’ be ‘x’, (x + 2) years, (x + 4) years and (x + 6) years, respectively According to question: x + x + 2 + x + 4 + x + 6 = 120 Or, 4x = 108 Or, x = 27 years (Age of A) Present age of ‘C’ = x + 4 = 27 + 4 = 31 years Required sum = 27 + 31 = 58 years
Statements: I ≤ J = K < L < M, G ≥ H = I = T
Conclusions: Â Â Â Â
 I. J > G
II. Â M = H
III. M > H
...Statements: P ≥ Q > R, S ≤ R, T = W ≥ R
Conclusions:
I. T ≥ S
II. Q < W
Statement: C ≥ O ≥ S = Z ≤ N = R
Conclusions:
I. C > N
II. S ≤ R
Statements:Â
A $ B * X © Y @ ZÂ
Conclusions:Â
I. X @ ZÂ
 II. Z * AÂ
III. Z % X
Statement: K = B; D ≥ L ≥ T ≥ B
Conclusion: I. D > K II. D = K
Statements: P # Q @ R & S @ T # W % I, K $ S @ L
Conclusions: I. Q # W II. R & L
...Statement: F < G; F ≥ H > I; D ≥ E > G
Conclusion:
I. I ≥ G
II. E ≥ F
Statements : Z < S < W < D; E ≤ C ≤ Y < D; U < T < S ≤ V
Conclusions :
I. V > Z
II. C < U
III. V > E
Statements: Q > R ≥ L = O ≤ M > S = T ≤ N
Conclusion
I: N ≤ L
II: N > L
