Question
A father is four times as old as his son. In 10 years,
the father will be twice as old as his son. What is the son’s present age?Solution
Let son’s present age = x Father’s present age = 4x After 10 years: Son = x + 10 Father = 4x + 10 Given: father will be twice son’s age 4x + 10 = 2(x + 10) 4x + 10 = 2x + 20 4x − 2x = 20 − 10 2x = 10 x = 5 Son’s present age = 5 years
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