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    Question

    A father is four times as old as his son. In 10 years,

    the father will be twice as old as his son. What is the son’s present age?
    A 10 yrs Correct Answer Incorrect Answer
    B 5 yrs Correct Answer Incorrect Answer
    C 8 yrs Correct Answer Incorrect Answer
    D 12 yrs Correct Answer Incorrect Answer

    Solution

    Let son’s present age = x Father’s present age = 4x After 10 years: Son = x + 10 Father = 4x + 10 Given: father will be twice son’s age 4x + 10 = 2(x + 10) 4x + 10 = 2x + 20 4x − 2x = 20 − 10 2x = 10 x = 5 Son’s present age = 5 years

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