Question
The present age of A is 9/5 times to that of his
marriage age. Present age of his brother is 1/2nd of his present age. If A was married 24 years ago then find the present age of his brother.Solution
Let the age of A when he was married be x years. Present age of A = 9x/5 Present age of his brother = (1/2) × (9x/5) = 9x/10 According to Question, => x + 24 = 9/5x => 4/5x = 24 => x = 30 years Present age of his brother = (9/10) × 30 = 27 years
50 62 ? 96 126 138
...89Â Â Â Â Â 78Â Â Â Â Â 74Â Â Â Â Â 67Â Â Â Â Â 63Â Â Â Â ?
4 6 ? 31 119 601
...Find the maximum number of trees which can be planted, 25 meters apart, on the two sides of a straight road 2125 meters long
55 46 60 41 65 36 ?
8 6 2 ? -1 9.5
...9999 6666 ? 2962.66 1975.11 1316. 74
...2, 17, 147, 1167, 8157, 48957
3,   2,   3,  8,  31,  ?
Study the given pattern carefully and select the number that can replace the question mark (?) in it.
4 7 6
15 ? 21
44 68 60