Question
Three years ago, age of A was 10 years less than 1.2 times
his current age. The ratio of age of B, 3 years later to the age of C, 1 year ago is 3:2. Find the age of B, if C is 40% less than A.Solution
ATQ,
Let the present age of A, B and C be ‘a’, ‘b’ and ‘c’ years respectively.
a – 3 = 1.2 × a – 10
0.2 × a = 7
a = 7 / 0.2
a = 35 years
So, age of c = 35 × 0.6 = 21 years
Also, (b + 3)/(c – 1) = 3/2
b + 3 = 1.5c – 1.5
b = 1.5 × 21 – 1.5 – 3
b = 31.5 – 4.5 = 27 years
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