Question
Three years ago, A’s age was 9 years less than 1.3 times
his current age. The ratio of B’s age after 4 years to C’s age 2 years ago is 3:1. What is B’s present age, if C is 45% less than A?Solution
ATQ,
Let the present age of A, B and C be ‘a’, ‘b’ and ‘c’ years respectively.
a – 3 = 1.3 × a – 9
0.3 × a = 6
a = 6 / 0.3
a = 20 years
So, age of c = 20 × 0.55 = 11 years
Also, (b + 4)/(c – 2) = 3/1
b + 4 = 3 × (11 – 2) = 3 × 9 = 27
b = 27 – 4 = 23 years
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