Question
Two years ago, the ages of A, B, and C were xβ6x - 6,
x+10x + 10, and x+14x + 14 years respectively. If the average of their current ages is 38 years, determine the value of x. .Solution
Present age of A = x β 6 + 2 = βx β 4β years Present age of B = x + 10 + 2 = βx + 12β years Present age of C = x + 14 + 2 = βx + 16β years 38 = [(x β 4) + (x + 12) + (x + 16)] / 3 3x + 24 = 114 x = 30
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