Question
 Present average age of A, B and C together is 44
years. Age of B is 12 Years hence from now will be 260% more than age of A. Four years ago from now while age of C after 12 years hence from now will be 50% more than the age of B 20 years ago from now. 4 years hence from now, what will be the ratio of ages of A and C?Solution
Let present age of A, B and C is a, b, and c respectively  So a+b+c = 44*3= 132--------(1)  And, (b+12) = 3.6*(a-4)  5b+60 = 18(a-4)  18a-5b=132---------(2)  And, (c+12) = 1.5*(b-20)  3b-2c=84---------(3)  Solving equation 1, 2 and 3 we get  a=24, b = 60, and c = 48  Age of A, B 4 years hence now will be 28 and 52 respectively.  Required ratio = 28:52 = 7:13 Â
- Find the wrong number in the given number series.
25, 36, 29, 40, 33, 50 154Â Â Â Â 165Â Â Â Â 143Â Â Â Â 175Â Â Â Â Â 132Â Â Â Â Â 187
...5000, 4500, 3600, 2480, 1512, 756Â Â Â
Find the wrong number in the given number series,
125, 150, 250, 475, 875, 1500
- Find the wrong number in the given number series.
5, 8, 12, 19, 27, 39 768Â Â Â 2304Â Â Â 288Â Â Â 864Â Â Â 106Â Â Â 324
Find the wrong number in the given number series.
5, 6, 14, 45, 188, 925
120, 240, 80, 320, 60, 384
21 32 54 86 131 186
... 7    12     33    126    635  Â
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