Question
Ratio of ages of A and B, after 10 years will be 9:5,
respectively. Present average age of A, B and C is 22 years. If present age of C is 50% more than age of A 6 years ago, then find the ratio of present ages of B and C respectively.Solution
ATQ, ATQ, Let ages of A and B, after 10 years be 9x years and 5x years, respectively. Present age of A = 9x β 10 years Present age of B = 5x β 10 years Present age of C = 22 Γ 3 β [(9x β 10) + (5x β 10)] = 66 β (14x β 20) = 86 β 14x years According to the question, Present age of C is 50% more than age of A 6 years ago Age of A, 6 years ago = 9x β 10 β 6 = 9x β 16 So, 1.5 Γ (9x β 16) = 86 β 14x Or, 13.5x β 24 = 86 β 14x Or, 13.5x + 14x = 86 + 24 Or, 27.5x = 110 Or, x = 4 Present age of B = 5 Γ 4 β 10 = 20 β 10 = 10 years Present age of C = 86 β 14 Γ 4 = 86 β 56 = 30 years Desired Ratio (B : C) = 10 : 30 = 1 : 3
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