Question
The present age of A is 7/4 times to that of his
marriage age. Present age of his brother is 1/4th of his present age. If A was married 36 years ago then find the present age of his brother.Solution
Let the age of A when he was married be x years. Present age of A = 9x/5 Present age of his brother = (1/2) × (9x/5) = 9x/10 According to Question, => x + 40 = 9/5x => 4/5x = 40 => x = 50 years Present age of his brother = (9/10) × 50 = 45 years
81% of 1550 + 27² = ? + 1386 ÷ 22
510.11 ÷ 16.98 × 5.14 – 119.9 = √?Â
(0.89 3 + 1.64 3 +2.76 3 ) ÷ 5.89 = ?
√3601 × √(224) ÷ √102 = ?
? = 540.24 + 1022.97 – 11.992 Â
What approximate value will replace the question mark (?) in the following?
18.99...
?% of 1499.89 + 54.14 × 8 = 25.05% of 5568.08
(289.89 + 59.98) X 2.25 = ? X 49.66
? × [(16.87) 2 – (6.98) 2 ] = 5.04× 191.11
? = 49.83% of 39.72% of (45.011.99 – 4.98 2.04)