Question
The present age of A is 7/4 times to that of his
marriage age. Present age of his brother is 1/4th of his present age. If A was married 36 years ago then find the present age of his brother.Solution
Let the age of A when he was married be x years. Present age of A = 9x/5 Present age of his brother = (1/2) × (9x/5) = 9x/10 According to Question, => x + 40 = 9/5x => 4/5x = 40 => x = 50 years Present age of his brother = (9/10) × 50 = 45 years
I. 2y² - 35y + 132 = 0
II. 2x² - 31x + 110 = 0
I. 195x² - 46x - 21 = 0
II. 209y² + 13y - 12 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 21x² - 122x + 160 = 0
Equation 2: 23y² - 159y + ...
I. 88x² - 13 x – 56 = 0
II. 15 y² + 41 y + 28 = 0
If x^2 - 7x + k = 0 has roots that are equal, what is the value of k?
I. x2 – 39x + 360 = 0
II. y2 – 36y + 315 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 37x² - 172x + 135 = 0
Equation 2: 29y² - 132y + ...
What will be the product of smaller roots of both equations.Â
I. 22x² - 97x + 105 = 0
II. 35y² - 61y + 24 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 45x + 450 = 0
Equation 2: y² - 48y + 540 = 0�...