Question
 The present ages of a father and his son sum to 54
years. Six years ago, father’s age was 5 times the son’s age. Son’s present age is:Solution
Let son = x, father = 54 − x 6 years ago: (54 − x − 6) = 5(x − 6) 48 − x = 5x − 30 78 = 6x ⇒ x = 13
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