Question
Present age of βKβ is 70% more than that of βLβ.
10 years ago, βKβ was 2.2 times as old as βLβ. Find the present age of βLβ.Solution
Let the present age of βLβ be βxβ years
Therefore, present age of βKβ = 1.7x years
ATQ;
(1.7x β 10) = 2.2 Γ (x β 10)
Or, 1.7x β 10 = 2.2x β 22
Or, 12 = 0.5x
Or, x = 24
Therefore, present age of βLβ = 24 years
