Question
Present age of ‘K’ is 70% more than that of ‘L’.
10 years ago, ‘K’ was 2.2 times as old as ‘L’. Find the present age of ‘L’.Solution
Let the present age of ‘L’ be ‘x’ years
Therefore, present age of ‘K’ = 1.7x years
ATQ;
(1.7x – 10) = 2.2 × (x – 10)
Or, 1.7x – 10 = 2.2x – 22
Or, 12 = 0.5x
Or, x = 24
Therefore, present age of ‘L’ = 24 years
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