Question
The present ages of A and B are in the ratio 4:5.
Sixteen years from now, B's age will be 15% more than A's age at that time. If C's current age is three times the difference between the present ages of A and B, what is C's present age?Solution
Let the present ages of 'A' and 'B' be '4x' years and '5x' years, respectively. ATQ; (4x + 16) X 1.15 = (5x + 16) Or, 4.6x + 18.4 = 5x + 16 Or, 0.4x = 2.4 So, x = 6 So, difference between ages of 'A' and 'B' = 5x - 4x = x = 6 years Or, 'p' = 6 So, present age of 'C' = 3p = 3 X 6 = 18 years
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