The sum of two numbers is 40. If one-third of the first number is subtracted from one-fourth of the second number, then the result is 3. What are the two numbers?
Let the first number be x and the second number be y. Then, x + y = 40 And, (1/4)y - (1/3)x = 3 Solving the two equations, we get x = 12 and y = 28. Therefore, the two numbers are 12 and 28
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