Question
If in the number '647315368', 1 added to all the odd
numbers, then what is the sum of the digits which are repeating more than two times in the new number thus formed? Note: While taking the sum the repeating digit is to be considered only once.Solution
6 4 7 3 1 5 3 6 8 6 4 8 4 2 6 4 6 8 So, the digits that are repeating more than two times are '6' and '4'. So, sum = (6 + 4) = 10.
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What is the highest common factor of (x³ - x² - x - 15) and (x³ - 3x² - 3x + 9)?
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