Question
A train of length 260 m crosses another train of length
120 m running is opposite direction in 5 sec. If speed of longer train is 90 km/h, then in what time smaller train will cross a tunnel of length 339 m?Solution
Let speed of smaller train be ‘x’ m/sec. Speed of longer train (m/sec) = 90 × (5/18) = 25 m/sec => (260 + 120) = (x + 25) × 5 => x + 25 = 76 => x = 51 m/sec Required time = (120 + 339)/51 = 9 sec
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