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Time taken by Manoj to complete the whole work = 7/0.35 = 20 days Time taken by Vipin to complete the whole work = 20/0.80 = 25 days Let the total work = 100 units (L.C.M of 20 and 25) Efficiency of Manoj = 100/20 = 5 units/day Efficiency of Vipin = 100/25 = 4 units/day Time taken by Manoj and Vipin to complete 36% of the work = 0.36 × 100/(5 + 4) = 4 days Amount of work done by Manoj and Vipin in 5 days = (5 + 4) × 5 = 45 units Remaining work = 100 – (36 + 45) = 19 units Therefore, 19x = 19 Or, x = 1 units/day Original efficiency of Ram = 1 × 8 = 8 units/day Time taken by Ram to complete 80% of work = (0.80 ×100)/8 = 10 days For I: (2x + 8) = 1 × 2 + 8 = 10 days Therefore, I can be the answer. For II: (10x – 2) = 7 × 1 – 2 = 8 days Therefore, II cannot be the answer. For III: (22x – 12) = 22 × 1 – 12 = 10 days Therefore, III can be the answer.
Calculate the simplified result of the following expression: 12 × 18 ÷ 3 + 36 of 32 ÷ 3
? (1/2) = 236 – 25 × 18/2 + 396 ÷ 22
Determine the simplified value of the expression: 12 × 15 - 20 + 15 + 12 - 18 + 3 × 4 + 18.
4.56 + 56.4 + 64.5 = ? + 10.46
What will come in the place of question mark (?) in the given expression?
? X 7 + (243)⁽²/⁵⁾ = 380 ÷ 2 + 71
If x²- 5x + 1 = 0, what is the value of x² + 1/x2?
36% of 640 – 12.5% of 352 + 25% of 640 = ? – 48% of 432
∛857375 + ∛91125 = ? + √6889