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    Question

    If the sum of the squares of the roots of p2

    - (x-2)p - (x+1) = 0 is 5 then what is the value of x.
    A 1 Correct Answer Incorrect Answer
    B -1 Correct Answer Incorrect Answer
    C 1/2 Correct Answer Incorrect Answer
    D -2 Correct Answer Incorrect Answer
    E -1/2 Correct Answer Incorrect Answer

    Solution

    Let the roots of equation be a and b. Given that, a2 + b2 = 5 We know that, (a+b )2 = a2 + b2 + 2ab Or, (a+b )2 тАУ 2ab = a2 + b2 Sum of roots = -(-(x-2)), product of roots = -(x + 1) (x тАУ 2)2 тАУ 2 ├Ч 1 ├Ч тАУ (x+1) = 5 Or, x2 + 4 тАУ 4x + 2x + 2 = 5 Or, x2 тАУ 2x + 1 = 0 Or, (p тАУ 1)2 = 0 Or, p = 1

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