Question
If Sin 3A = Cos (A - 46°) where 3A is acute angle,
then the Value of A isSolution
Sin 3A = Cos (A - 46°) Sin 3A = Sin [90° -(A - 46°)] 3A = 90° - A + 46° 4A = 136° A = 34°
48 24 24 48 ? 1536
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