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    • Question

      The minimum value of 45 sin2 θ + 28

      cos2 θ is
      A 28 Correct Answer Incorrect Answer
      B 39 Correct Answer Incorrect Answer
      C 14 Correct Answer Incorrect Answer
      D 12 Correct Answer Incorrect Answer

      Solution

      The minimum  value of  asin 2 θ + bcos 2 θ  is   =  Lesser value between a & b. So the minimum  value of  45 sin 2 θ + 28 cos 2 θ  is  = Lesser value between  45 & 28 = 28

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