Question
The minimum value of 45 sin2 θ + 28
cos2 θ isSolution
The minimum  value of asin 2 θ + bcos 2 θ  is  = Lesser value between a & b. So the minimum  value of 45 sin 2 θ + 28 cos 2 θ  is = Lesser value between  45 & 28 = 28
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