Question
A train of length (L + 90) meters crosses a man running
in the same direction in 30 seconds. The same train crosses a bridge of length (L - 210) meters in 36 seconds. If the speed of the man is 18 kmph, then find the value of 'L'.Solution
Let the speed of the train be 'S' m/s,
Speed of the man = 18 kmph = 5 m/s
Length of the train = (L + 90) metres
ATQ,
L + 90 = (S - 5) X 30
L = 30S - 240 --- (i)
Sum of the length of Train and bridge = L + 90 + L - 210
= (2L - 120) metres
Now,
2L - 120 = 36S
Using value of 'L' from equation (i), we get:
2 X (30S - 240) - 120 = 36S
Or, 60S - 480 - 120 = 36S
Or, 24S = 600
So, 'S' = 25
Required value of 'L' = 30 X 25 - 240 = 510
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