Question
A freight train requires 17.6 seconds to pass a
stationary person and 28 seconds to traverse a 260-meter-long tunnel. Simultaneously, a motorcycle can cross a 315-meter-long bridge in 15 seconds. Determine the time needed for the train to entirely overtake the bike.Solution
ATQ, Let the length of the freight trains = 'l' meters Then, distance travelled by the freight  trains in 17.6 seconds = 'l' meters Distance travelled by the Freight  train in 28 seconds = (l + 260) meters So, distance travelled by the freight train in (28 - 17.6) seconds = l + 260 - l = 260 meters So, speed of the Freight train = 260 ÷ 10.4 = 25 m/s And so, length of the freight train = 25 × 17.6 = 440 meters Speed of the bike = 315 ÷ 15 = 21 m/s So, relative speed of the freight train w.r.t to the bike = 25 - 21 = 4 m/s And so, time taken by the freight train to completely overtake the bike = 440 ÷ 4 = 110 seconds
20% of 1500 – 75% of 200 = 125% of ?Â
24% of 150% of 500 + 140 = ? × 8Â
458.32 - 563.32 + 659.32 =?
What will come in the place of question mark (?) in the given expression?
(√1089 + 84 ÷ 2) % of 348 = 416 - ?
40% are the passing marks. A student gets 250 marks yet fails by 38 marks. What is the maximum marks?
(22.5 × 24) ÷ 40 + 51.50 = ? ÷ 5.25
36×?² + (25% of 208 +13) = 60% of 2400 + 17×18
What will come in the place of question mark (?) in the given expression?
√64 X 9 ÷ 3 + 12 X 3 = ? + 36(3/7) x 868 + 25% of 240 = (? + 65)
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