Question
Train ‘A’ running with a speed of 108 km/hr
crosses a vertical pole in 13 seconds. Find the approx. time taken by the train ‘A’ to cross a train ‘B’ whose length is 110 metres less than that of train ‘A’ and whose speed is 1/3 more than that of train ‘A’ if both are running in opposite direction.Solution
Speed of train ‘A’ = 108 × (5/18) = 30 m/sec
Length of train ‘A’ = 30 × 13 = 390 metres
Length of train ‘B’ = 390 – 110 = 280 metres
Speed of train ‘B’ = 30 + (30/3) = 40 m/sec
Required time taken = (390 + 280)/(30 + 40) = 9.57 = 10 seconds
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