Question
Train ‘A’ running with a speed of 108 km/hr crosses
a vertical pole in 12 seconds. Find the approx. time taken by the train ‘A’ to cross a train ‘B’ whose length is 140 metres less than that of train ‘A’ and whose speed is 1/4 more than that of train ‘A’ if both are running in opposite direction.Solution
Speed of train ‘A’ = 108 × (5/18) = 30 m/sec Length of train ‘A’ = 30 × 12 = 360 metres Length of train ‘B’ = 360 – 140 = 220 metres Speed of train ‘B’ = 30 + (30/4) = 37.5 m/sec Required time taken = (360 + 220)/(30 + 37.5) = 8.59 = 9 seconds
More Trains Questions
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
? = 41.92% of 49.96% of (45.07 1.97 – 4.98 2.03 )
(15.15 × 31.98) + 30.15% of 719.99 = ? + 124.34
15.2 x 1.5 + 258.88+ ? = 398.12 + 15.9
784.69 + 86.96 ÷ 29.01 = 40.01 + ? + 367.88
(29.892 × √290) + 32.98 × 6.91 = ?
(15.87% of 79.98 + 19.69% of 64.22) × 4.83 = ?
(3/5) of 3025 + (18² + 12²) = ? + 22.22% of 1125
24.75% of 20.125% of 30.05% of 2196.06 = ?
(799.81/64) ÷ (10/799.92) × (129.84/130) = ?
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