Question
Two buses, ‘X’ and ‘Y’, started simultaneously
from city ‘M’ and city ‘N’ towards each other. When they crossed each other after 6 hours, bus ‘Y’ had travelled 90 km more than bus ‘X’. What is the distance covered by bus ‘X’ in 4 hours if the total distance between city ‘M’ and ‘N’ is 510 km?Solution
ATQ,
Let the distance travelled by bus ‘X’ when they crossed each other = ‘x’ km Then, the distance covered by bus ‘Y’ = x + 90 km According to question, x + x + 90 = 510 Or, 2x = 420 Or, x = 210 Distance travelled by bus ‘X’ in 6 hours = 210 km Speed of bus ‘X’ = 210 / 6 = 35 km/h Distance travelled by bus ‘X’ in 4 hours = 35 × 4 = 140 km
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