Question
Two buses, βXβ and βYβ, started simultaneously
from city βMβ and city βNβ towards each other. When they crossed each other after 6 hours, bus βYβ had travelled 90 km more than bus βXβ. What is the distance covered by bus βXβ in 4 hours if the total distance between city βMβ and βNβ is 510 km?Solution
ATQ,
Let the distance travelled by bus βXβ when they crossed each other = βxβ km Then, the distance covered by bus βYβ = x + 90 km According to question, x + x + 90 = 510 Or, 2x = 420 Or, x = 210 Distance travelled by bus βXβ in 6 hours = 210 km Speed of bus βXβ = 210 / 6 = 35 km/h Distance travelled by bus βXβ in 4 hours = 35 Γ 4 = 140 km
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