Question
Train A when travelling with a speed of 108 km/h crosses a
pole in 8 seconds. Find the time taken by the train A to cross another train B of length 50% more than that of train A which is coming from the opposite direction with a speed of 72 km/h.Solution
Speed of train A = 108 × 5/18 = 30 m/s
Length of train A = 30 × 8 = 240 metres
Length of train B = 1.5 × 240 = 360 metres
Speed of train B = 72 × 5/18 = 20 m/s
Relative speed = 30 + 20 = 50 m/s (opposite direction)
Total distance = 240 + 360 = 600 metres
Desired time = 600/50 = 12 seconds
A device used for converting A.C. into D.C. is called –
The magnetic equator is closely associated with which of the following?
Parsec is the unit of
The law of reflection states that the angle of incidence is equal to the angle of reflection. What is the angle of incidence when the angle of reflectio...
Ultrasonic waves, propagating through a medium, can be detected by:
A body of mass 2 kg is moving with velocity 3 m/s. What is its kinetic energy? Â
The energy emitted by the Sun is due to
What is the density of an object with mass 500 g and volume 250 cm³? Â
Two point charges +q and −q are separated by a distance 2a. The electric field at a point on the perpendicular bisector at distance r from center is p...
What is the main effect of increasing the temperature of a gas at constant volume? Â