Question
Train A when travelling with a speed of 108 km/h crosses a
pole in 8 seconds. Find the time taken by the train A to cross another train B of length 50% more than that of train A which is coming from the opposite direction with a speed of 72 km/h.Solution
Speed of train A = 108 × 5/18 = 30 m/s
Length of train A = 30 × 8 = 240 metres
Length of train B = 1.5 × 240 = 360 metres
Speed of train B = 72 × 5/18 = 20 m/s
Relative speed = 30 + 20 = 50 m/s (opposite direction)
Total distance = 240 + 360 = 600 metres
Desired time = 600/50 = 12 seconds
More Trains Questions
12.5% of (100 + ?) = 40
2/9 of 5/8 of 3/25 of ? = 40
24 × √? + 4008 ÷ 24 = 40% of 200 + 327
7(1/2) – 3(5/6) = ? − 2(7/12)
280 ÷ 14 + 11 × 12 – 15 × 6 = ?
1550 ÷ 62 + 54.6 x 36 = (? x 10) + (28.5 x 40)
25% of 1000 + 10% of 150 – 22 × ? = 45
√ 729 × 5 – 220 % of 15 + ? = 120% of 160
What will come in the place of question mark (?) in the given expression?
(40% of ? × 43 ) – 232 = 751
180 % of 45 + √144 × 8 = ?2 + 80 % of 70
Relevant for Exams:
