Question
A train crosses a pole in 12 seconds and crosses a
platform 168 m long in 26 seconds. Find the length of the train.Solution
ATQ, Let the length of the train be x m. Speed = x/12 m/s When crossing platform: Distance = x + 168 So, (x + 168)/26 = x/12 12(x + 168) = 26x 12x + 2016 = 26x 14x = 2016 x = 144
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