Question
A train of length βxβ m crosses a βx + 360β m
long platform in 60 seconds. If the train crosses a tree in 18 seconds, then find the value of βxβ.Solution
Speed of train = x/18 m/s So, (x + x + 360)/(x/18) = 60 2x + 360 = 10x/3 x = 270 So, the value of βxβ is 270 m.
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