Question
A train traveling at a velocity of 45 km/h passes a
stationary object in 36 seconds. Calculate the time it takes for the train to traverse a platform that is 600 meters in length.Solution
ATQ, Let, length of train be βdβ meter S = d/t So, 45 Γ (5/18) = d/36 d = 450 meter Length of the train = 450 meter 45 Γ (5/18) = (450 + 600)/t 12.5 = 1050/t t = 84 seconds
1500 Γ 60% of 25% = ? 2Β
[1.45 X 1.45 X 1.45 + 0.55 X 0.55 X 0.55 + 4.785] = ?
72 + 122 - 25% of 600 = ?
22 * 6 + 45% of 90 + 65% of 180 = ?
- What will come in place of (?) in the given expression.
β324 + β121 β β49 = ? 5.5 × 3.2 × 2.3 = ?
What will come in the place of question mark (?) in the given expression?
(β676 of β144 Γ· 13) of 2400% = ?Β
65% of 102 + 14 = ? β 20
? = β2704 Γ· (25% of 104) + 73
375% of 320 - 80% of 40 Γ· β256 = ?