Question
Train βAβ running with a speed of 54 km/hr can cross
a standing goods train of 4 times its length in 30 seconds. Find the time taken by 310 metres long train βBβ which is coming from opposite direction of train βAβ, with a speed of 20 m/s, to cross train βAβ.Solution
Let the length of train βAβ be βxβ metres Therefore, length of the goods train = β4xβ metres Speed of train βAβ = 54 Γ (5/18) = 15 m/s According to the question, 4x + x = 15 Γ 30 => 5x = 450 => x = 90 Therefore, time taken by train βBβ to cross train βAβ = {(90 + 310)/(30 + 20)} = 8 seconds
A pond of water appears less deep due to β
Which law states that the ratio of the potential difference across a conductor to the current through it is constant, provided the temperature remains c...
When white light passes through a glass prism, which color deviates the least?

The weight (W) of a body is derived from which formula?
What is the momentum of a 2 kg object moving at 3 m/s?Β Β
In an experimental arrangement of a Fresnel's biprism, monochromatic light of wavelength 2. is used to produce interference fringe pattern. On introduc...
Parsec is the unit of
Match the following machines with their working principles:
(i) Electric motor -Β (a) Heat energy into mechanical energy
(ii) Steam engin...
What happens to the electrostatic force between two charges when the distance between them decreases?Β