Question
In the Reebok factory, there are two units of workers, I and II, with a strength ratio of 2:1. The ratio of male to female in Unit I is 3:1, and in Unit II, it is 3:5. Workers from both units are arranged in rows of male and female, with each row having an equal number of workers. If the maximum number of workers possible in a row is 96, what is the difference between the number of males in Unit I and Unit II?.
Solution
ATQ, Let the strength of Unit I = 16k and that of = 8k Unit I ratio of Male: female = 3 : 1 → male = 12k and female = 4k Unit II ratio of Male: female = 3 : 5 → Male = 3k and female = 5k (I + II) – Male = 15k and Female = 9k Maximum number of workers in a row = HCF (15k, 9k) = 3k → 3k = 96 → k=32 Difference between Male of Unit I and II = 12k – 3k = 9k → 9 × 32 = 288
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