Let A’s amount be x. C now having the amount of Rs. 2400, => [x × (45/100) × (2/3)] – 240 = 2400 => x × (45/100) × (2/3) = 2640 => x = 2640/0.3 => x = 8800 A initially having an amount of Rs. 8800.
124.88% of 60.101 + 18.09% of 849.87 – 22.12% of 1049.93= ? – 19.93
(?)2 + 8.113 = 28.92 – 73.03
1254.04 – 440.18 + 399.98 ÷ 10.06 = ?
(22.9)3 + (30.021)² - (19.11)3 - (44.98)² = ?
(1.01) 0 + (2.02) 1 + (2.93) 2 + (4.04) 3 + (5.05) 4 = ?
(44.11/4.01) + (11.99/3.03) + 23.9% of 49.978 = ?3.03
7.992 + (4.01 × 3.98) + ? = 224.03
33.33% of 110.99 = 19.98% × 244.97 - √?
59.978% of 800.315 - 229.95 = ? - 24.95% of 200.15
149.78% of 319.87 – 199.83% of 45.45 = 130.03% of (? × 12.01)