Question
A train started from station P and preceded towards
station Q at a speed of 54 km/h. 40 minutes later, another train started from station Q and preceded towards station P at 100 km/h. If the distance between the two stations is 806 km, at what distance from station P will the trains meet?Solution
Let the train will meet ‘t’ hours after the train from station Q started Distance travelled by train started from station P = 54 x 40/60 km Distance travelled by train started from station Q = (54 + 100) x t km Total distance between station P and Q = 806 km Now, 54 x (40/60) + (54 + 100) x t = 806 ⇒ 40 + 154t = 806 ⇒ 154t = 806 – 40 = 770 ⇒ t = 770/154 = 5 hours Distance travelled by train starting from station P at all meeting point = 36 + 54 x 5 = 306 km
- Suppose both the roots of q² + kq + 49 = 0 are real and equal, then determine the value of 'k'.
I. 84x² - 167x - 55 = 0
II. 247y² + 210y + 27 = 0
l). 2p² + 12p + 18 = 0
ll). 3q² + 13q + 12 = 0
I. 2x² - 9x + 10 = 0
II. 3y² + 11y + 6 = 0
I. 6x2 - 47x + 77 =0
II. 6y2 - 35y + 49 = 0
I. 12a2 – 55a + 63 = 0
II. 8b2 - 50 b + 77 = 0
...I. 2y2 – 19y + 35 = 0
II. 4x2 – 16x + 15 = 0
I. 5x² - 24 x + 28 = 0
II. 4y² - 8 y - 12= 0
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer
I. x2 – ...
I.8(x+3)+ 8(-x)=72
II. 5(y+5)+ 5(-x)=150
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