I. 8(x+3)+ 8(-x)=72 8x × 83+ (1/8)x - 72=0 Let 8x=a 512a+ 1/a- 72=0 512a2+1-72a=0 512a²-72a+1=0 512a²-64a-8a+1=0 64a (8a-1)-1 (8a-1)= 0 (64a-1)(8a-1)= 0 a= 1/8,1/64 8x= 1/8 x= -1 8x= 1/64 x= -2 II.5(y+5)+ 5(-y)=150 55 × 5(y )+ (1/5)y -150=0 Let 5y=b 3125b+ 1/b - 150=0 3125b² - 150b + 1=0 3125b² - 125b - 25b + 1=0 125b(25b-1) - 1(25b-1) = 0 b = 1/25,1/125 5y= 1/25 y= -2 5y= 1/125 y= -3 Hence, x≥ y
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