Question
In each of these questions, two equations (I) and (II)
are given.You have to solve both the equations and give answer  I. x2 – 26x + 168 = 0   II. 2y2 - 19y – 60 = 0Solution
if signs of quadratic equation is -ve and +ve respectively then the roots of equation will be +ve and +ve.  So, roots of first equation = x = -16/3, 1 if signs of quadratic equation is -ve and -ve respectively then the roots of equation will be +ve and -ve. So, roots of second equation = y = 12, -5/2 After comparing roots of quadratice eqution we can conclude that x ≥ y.
The lengths of three medians in a triangles are 9 cm, 12 cm, 15 cm. What is the area of that traingle (in cm 2 )?
PQRS is a cyclic quadrilateral of which PQ is the diameter. Diagonals PR and QS intersect at A. If SQR = 25°, then angle PAS measures
Find the difference between angle and its complement if the angle is five-thirteenth of its complement.
A rectangle with a diagonal of length 28m is inscribed in a circle. Find the area of a circle?
In ∆ABC , G is the centroid , AB = 5 cm, BC= 8 cm and AC = 7 cm , find GD, where D is the mid-point of BC?
If in a ΔABC, D is a point on BC such that BD = 5cm , BC = 9 cm then what is ratio of area of ΔABD to area of ΔADC ?
ABC is a triangle. AB = 5 cm, AC = √41 cm and BC = 8 cm. AD is perpendicular to BC. What is the area (in cm2) of triangle ABD?
In the figure given below, AC = 16 cm and BF = 5 cm. If AE:CE = 5:3, then find the perimeter of ΔABC.
The length of the each side of an equilateral triangle is 28 cm. The area of incircle, (cm 2 ) is