Question
X can build a wall in 15 days, Y can build same wall in
25 days and Z can destroy the same wall in 30 days. If X & Y worked together for P days after that Z joined them. Now they all together completed the rest of the work in (P+15/11) days. In how many days total work will be completed?Solution
Let total work = LCM(15, 25, 30) = 150 units So, ratio of 1 day work by X, Y & Z respectively = 10 : 6 : (-5) According to question, P(10+6) + (P+15/11) × (10+6-5) = 150 16P + (P+15/11) × (11) = 150 16P + 11P + 15 = 150 27P = 135 P = 5 So total days = P + (P + 15/11) = 5 + 5 + 15/11 = 10 + 15/11 = 125/11 days.
√3598 × √(230 ) ÷ √102= ?
15% of 2400 + (√ 484 – √ 256) = ?
(13)2 - 3127 ÷ 59 = ? x 4
6269 + 0.25 × 444 + 0.8 × 200 = ? × 15
...(53 + 480 ÷ 4)% of 20 = ?% of 70
Find the simplified value of the following expression:
62 + 122 × 5 - {272 + 162 - 422}
(15 × 225) ÷ (45 × 5) + 480 = ? + 25% of 1240
√ [? x 11 + (√ 1296)] = 16
11 × 25 + 12 × 15 + 14 × 20 + 15 = ?