Question
A can complete a work in 15 days and B can complete the same work in 20 days. They work together for 5 days. If after that B's efficiency increases by 25%, then in how many more days will B alone complete the remaining work?
Solution
ATQ, A's 1-day work = 1/15 B's 1-day work = 1/20 Together = 1/15 + 1/20 = 4/60 + 3/60 = 7/60 Work done in 5 days = 35/60 = 7/12 Remaining work = 1 - 7/12 = 5/12 B's efficiency increases by 25% Original time of B = 20 days New time = 20/1.25 = 16 days New 1-day work of B = 1/16 Time to complete remaining work = (5/12) x 16 = 20/3
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