Question
A and B together can complete a work in 10 days. B alone
can complete the same work in 25 days. In how many days can A alone complete the work?Solution
ATQ, Let total work = LCM(10, 25) = 50 units. (A + B)’s 1-day work = 50/10 = 5 units B’s 1-day work = 50/25 = 2 units So A’s 1-day work = 5 − 2 = 3 units Time taken by A alone = 50 / 3 days = 16⅔ days
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