Question
'P' and 'Q' can complete a task in 36 days together. If
'P' alone can do it in 60 days, how long would 'Q' take to finish the task alone?Solution
ATQ,
Let the total work be 180 units. {LCM (36 and 60)} So, combined efficiency of 'P' and 'Q' = 180 ÷ 36 = 5 units/day Efficiency of 'P' = 180 ÷ 60 = 3 units/day So, efficiency of 'Q' = 5 - 3 = 2 units/day So, time taken by 'Q' to do the work alone = 180 ÷ 2 = 90 days
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