Question
P and Q can complete a work in 20 days and 30 days,
respectively. P, Q and R together can complete the work in 10 days. If R get a total wage of Rs. 4800 to complete the work alone, then find the per day wage of R.Solution
Let the total work be LCM of (20, 30 and 10) = 60 units Number of units of work done by P alone in one day = 60/20 = 3 units Number of units of work done by Q alone in one day = 60/30 = 2 units Number of units of work done by P, Q and R together in one day = 60/10 = 6 units Number of units of work done by R alone in one day = 6 – 3 – 2 = 1 unit So, time taken by R alone to complete the work = 60/1 = 60 days So, per day wage of R = 4800/60 = Rs. 80
230 192 172 ? 122 100
...What value should come in the place of (?) in the following number series?
64, 80, 104, ?, 176, 224
97, 106, ?, 195, 411, 460
What will come in place of the question mark (?) in the following series?
29, 42, ?, 95, 135, 184
Find the missing term:
2, 6, 15, 31, 56, ?
32   48   96   ?   720   2520
82, 98, 130, 178, 242, ?
4 10 ? 62.5 156.25 390.625
...140, 146, 170, 224, ?, 470
7 47 ? 223 359 527
...
