Question
A firm assigned 10 technicians to complete an assignment in
30 days. After 12 days of work, 4 technicians were moved to another location. What is the extension in the deadline?Solution
ATQ,
Let efficiency of each technician = 'e' units/day
Total work = 10 × 30 × e = 300e units
Work done in 12 days = 10 × 12 × e = 120e units
Remaining work = 300e - 120e = 180e units
Remaining technicians = 10 - 4 = 6
Time needed = 180e ÷ (6 × e) = 30 days
Extra days = 30 - 18 = 12 days
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